 Aptitude Tests 4 Me

Basic Numeracy/Quantitative Aptitude

Detailed Solution

49. b: Let x be the original price and y be the absolute decrease. If the price was decreased to \$30, then
x - y = 30
y is given by
y = 22% of x = (22 / 100) * x = 0.22 x
Substitute y by 0.22 x in the equation x - y = 30 and solve for x which the original price.
x - 0.22 x = 30
0.78 x = 30
x = \$38.5

50. b: First decrease in percent
part / whole = (120 - 100) / 120 = 0.17 = 17%
Second decrease in percent
part / whole = (100 - 80) / 100 = 0.20 = 20%
The second decrease was larger in percent term. The part were the same in both cases but the whole was smaller in the second decrease.

51. d: We first need to find the original price x. The first decrease gives x - 20% x = 200
0.8 x = 200
x = 200 / 0.8 = 250
The percentage decrease fro the original price 250 to 150 is given by part / whole = (250 - 150) / 250 = 0.4 = 40%

52. a: Percent increase from 30 to 40 is given by
(40 - 30) / 30 = 10 / 30 = 0.33 = 33% (2 significant digits)
Percent decrease from 40 to 30 is given by
(40 - 30) / 40 = 0.25 = 25%
In absolute term, the percent decrease is less than the percent increase.

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