 Aptitude Tests 4 Me

Basic Numeracy/Quantitative Aptitude

Detailed Solution

122. c: The correct answer is 1 in 20.
You must draw \$20, \$5, and \$50 since they are the only three bills that total \$75. The odds of drawing one of the needed bills is 1/2. The odds of drawing another needed bill is 2/5. The odds of drawing the last needed bill is 1/4. When you multiply the three fractions, you get 2/40 or 1/20.

123. a: The correct answer was 61 out of 125.
First I'll figure out the odds that you will not be found. The probability of one cop not finding you is 4/5. The probability of three cops not finding you would be 4/5 * 4/5 * 4/5 = 64/125.
This means that 61/125 is the probability that you will be found.

124. a: The correct answer is 169/425.
There are 4 sets of 13 cards of the same suit, so there is a 39/51 chance that the second card will be a different suit. The probability of the third card being a different suit than the others is only 26/50 or 13/25. When you multiply 39/51 * 26/50 you get 1014/2550, or 169/425.

125. a: Let x be the side of the smaller square and y be the side of the larger square.
The statment "A square has a side 5 centimeters shorter than the side of a second square" may be formulated by x = y � 5 For the second solution y = 10 / 3, x is negative and cannot be accepted as the length of the side of a square must be positive.

126. Use b = 26 - a to find b
when a = 11 , b = 15 and when a = 15 , b = 11.
The two numbers are 11 and 15.

127. a: Let x and y be the length and width of the rectangle. Using the formulas for the area and the perimeter, we can write two equations.
15 = x y and 16 = 2 x + 2 y
Solve the second equation for x
x = 8 - y
Substitute x in the equation 15 = x y by 8 - y to rewrite the equation as 15 = (8 - y) y
Solve for y to find y = 3 and y = 5
Use x = 8 - y to find x
when y = 3 , x = 5 and when y = 5 , x = 3.
The dimensions of the rectangle are 3 and 5.

128. a: Let x and y be the two numbers such that x is larger than y. The statement "the larger number is four less than twice the smaller number" may be formulated by x = 2y - 4
We use the sum of the two numbers to write a second equation.
x + y = 20
Substitute x by 2y - 4 in x + y = 20 to obtain 2y - 4 + y = 20
Solve for y to find y = 8 and x = 2y - 4 = 12

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