1. Passage Reading
2. Verbal Logic
3. Non Verbal Logic
4. Numerical Logic
5. Data Interpretation
6. Reasoning
7. Analytical Ability
8. Quantitative Aptitude

122. c: The correct answer is 1 in 20.

You must draw $20, $5, and $50 since they are the only three bills that total $75.
The odds of drawing one of the needed bills is 1/2. The odds of drawing another
needed bill is 2/5. The odds of drawing the last needed bill is 1/4. When you
multiply the three fractions, you get 2/40 or 1/20.

123. a: The correct answer was 61 out of 125.

First I'll figure out the odds that you will not be found. The probability of one cop
not finding you is 4/5. The probability of three cops not finding you would be 4/5 *
4/5 * 4/5 = 64/125.

This means that 61/125 is the probability that you will be found.

124. a: The correct answer is 169/425.

There are 4 sets of 13 cards of the same suit, so there is a 39/51 chance that the
second card will be a different suit. The probability of the third card being a
different suit than the others is only 26/50 or 13/25. When you multiply 39/51 *
26/50 you get 1014/2550, or 169/425.

125. a: Let x be the side of the smaller square and y be the side of the larger
square.

The statment "A square has a side 5 centimeters shorter than the side of a
second square" may be formulated by
x = y – 5

For the second solution y = 10 / 3, x is negative and cannot be accepted as the length of the side of a square must be positive.

126.

Use b = 26 - a to find b

when a = 11 , b = 15 and when a = 15 , b = 11.

The two numbers are 11 and 15.

127. a: Let x and y be the length and width of the rectangle. Using the formulas for
the area and the perimeter, we can write two equations.

15 = x y and 16 = 2 x + 2 y

Solve the second equation for x

x = 8 - y

Substitute x in the equation 15 = x y by 8 - y to rewrite the equation as
15 = (8 - y) y

Solve for y to find
y = 3 and y = 5

Use x = 8 - y to find x

when y = 3 , x = 5 and when y = 5 , x = 3.

The dimensions of the rectangle are 3 and 5.

128. a: Let x and y be the two numbers such that x is larger than y. The statement
"the larger number is four less than twice the smaller number" may be formulated
by
x = 2y - 4

We use the sum of the two numbers to write a second equation.

x + y = 20

Substitute x by 2y - 4 in x + y = 20 to obtain
2y - 4 + y = 20

Solve for y to find
y = 8 and x = 2y - 4 = 12

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