aptitudetests4me.com
Aptitude Tests 4 Me

Download Free EBooks for Various Types of Aptitude Tests


1. Passage Reading 2. Verbal Logic 3. Non Verbal Logic 4. Numerical Logic 5. Data Interpretation 6. Reasoning 7. Analytical Ability 8. Quantitative Aptitude

Basic Numeracy/Quantitative Aptitude

Detailed Solution

122. c: The correct answer is 1 in 20.
You must draw $20, $5, and $50 since they are the only three bills that total $75. The odds of drawing one of the needed bills is 1/2. The odds of drawing another needed bill is 2/5. The odds of drawing the last needed bill is 1/4. When you multiply the three fractions, you get 2/40 or 1/20.

123. a: The correct answer was 61 out of 125.
First I'll figure out the odds that you will not be found. The probability of one cop not finding you is 4/5. The probability of three cops not finding you would be 4/5 * 4/5 * 4/5 = 64/125.
This means that 61/125 is the probability that you will be found.

124. a: The correct answer is 169/425.
There are 4 sets of 13 cards of the same suit, so there is a 39/51 chance that the second card will be a different suit. The probability of the third card being a different suit than the others is only 26/50 or 13/25. When you multiply 39/51 * 26/50 you get 1014/2550, or 169/425.

125. a: Let x be the side of the smaller square and y be the side of the larger square.
The statment "A square has a side 5 centimeters shorter than the side of a second square" may be formulated by x = y – 5

For the second solution y = 10 / 3, x is negative and cannot be accepted as the length of the side of a square must be positive.

126.

Use b = 26 - a to find b
when a = 11 , b = 15 and when a = 15 , b = 11.
The two numbers are 11 and 15.

127. a: Let x and y be the length and width of the rectangle. Using the formulas for the area and the perimeter, we can write two equations.
15 = x y and 16 = 2 x + 2 y
Solve the second equation for x
x = 8 - y
Substitute x in the equation 15 = x y by 8 - y to rewrite the equation as 15 = (8 - y) y
Solve for y to find y = 3 and y = 5
Use x = 8 - y to find x
when y = 3 , x = 5 and when y = 5 , x = 3.
The dimensions of the rectangle are 3 and 5.

128. a: Let x and y be the two numbers such that x is larger than y. The statement "the larger number is four less than twice the smaller number" may be formulated by x = 2y - 4
We use the sum of the two numbers to write a second equation.
x + y = 20
Substitute x by 2y - 4 in x + y = 20 to obtain 2y - 4 + y = 20
Solve for y to find y = 8 and x = 2y - 4 = 12


1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40
41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60
61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80
81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100
101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120
121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140
141 142 143 144 145 146 147 148 149 150 151 152 153 154 155 156 157 158 159 160
161 162 163 164 165 166 167 168 169 170 171 172 173 174 175 176 177 178 179 180
181 182 183 184 185 186 187 188 189 190 191 192 193 194 195 196 197 198 199 200
201 202 203 204 205 206 207 208 209 210 211 212 213 214 215 216 217 218 219 220
221 222 223 224 225 226 227 228 229 230 231 232 233 234 235 236 237 238 239 240
241 242 243 244 245 246 247 248 249 250 251 252 253 254 255 256 257 258 259 260
261 262 263 264 265 266 267 268 269 270 271

bulletPassage Reading bulletVerbal Logic bulletNon Verbal Logic bulletNumerical Logic bulletData Interpretation bulletReasoning bulletAnalytical Ability bulletBasic Numeracy bulletAbout Us bulletContact bulletPrivacy Policy bulletMajor Tests bulletFAQ