Aptitude Tests 4 Me

Basic Numeracy/Quantitative Aptitude

Detailed Solution

233. The best answer is D.
The gender of the first-born is insignificant since we want all children to be of the same gender no matter if they are all boys or girls. The probability for the second child to be of the same gender as the first is: ½. The same probability goes for the third child. Therefore the answer is ½ x ½ = ¼.

234. The best answer is D.
The coin is tossed three times therefore there are 8 possible outcomes (2 x 2 x 2). We are interested only in the three following outcomes:
(0,1,1), (1,0,1), (1,1,0).
The probability requested is 3/8.

235. The best answer is A.
We want to make a 3-flower garlands, each should have three colors of flowers in it.
There are two different types of blue and two different types of red.
The options are (2 blue) x (2 red) x (1 yellow) = 4 options.

236. The best answer is A.
If 1/8 is the probability of drawing a blue ball then there are 40/8 = 5 blue balls in the jar. And with the same principle there are 8 red balls and 4 green ones. 40 – 5 – 8 – 4 = 23 balls (yellow is the only color left).

237. The best answer is A.
Since we want to draw at least one red ball we have four different possibilities:
1. Drawing blue-blue.
2. Drawing blue-red.
3. Drawing red-blue.
4. Drawing red-red.
There are two ways to solve this question:
One minus the probability of getting no red ball (blue-blue):
1-2/5 x ¼ = 1-2/20 = 18/20 = 9/10/
Or summing up all three good options:
Red-blue --> 3/5 x 2/4 = 6/20.
Blue-red --> 2/5 x ¾ = 6/20.
Red-red --> 3/5 x 2/4 = 6/20.
Together = 18/20 = 9/10.

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