Aptitude Tests 4 Me

Basic Numeracy/Quantitative Aptitude

Detailed Solution

332. 75. Solution. Since one of the integers is 5, the product of the other two is 60 (5 x 60 = 300).
Systematically, list all possible pairs, (a, b), of positive integers whose product is 60, and check their sums. First, let a =1, then 2, and so on.

333. Solution. First, write down
the numbers in the 100’s 101, 111, 121, 131, 141, that end in 1: 151, 161, 171, 181, 191
Now write the numbers 202, 212, 222, 232, 242, beginning and ending in 2: 252, 262, 272, 282, 292
By now you should see the pattern: there are 10 numbers beginning with 1, and 10 beginning with 2, and there will be 10 beginning with 3, 4, ..., 9 for a total of 9 x10 = 90 palindromes.

334. Solution. Represent the five boys as A, B, C, D, and E. Placing Charlie last, you see that the order is B __ __ __ C. Systematically fill in the blanks with A, D, and E. Write all the three letter “words” you can in alphabetical order so you don’t accidentally skip one.
A D E
A E D
D A E
D E A
E A D
E D A
There are 6 possibilities when C is last. Clearly, there will be 6 more when D is last. Therefore, there are 12 ways in all to satisfy the conditions of the problem.

335.

336. Solution. Since you can trust the chart to be accurate, the total number of electoral votes for the six states is 4 + 4 + 3 + 13 + 4 + 8 = 36
and the average is 36 _ 6 = 6 (C).

337. The definition of “_” tells you that, whenever two numbers surround a “happy face,” you are to form a fraction in which the numerator is the sum of the numbers and the denominator is their difference. Here, 25 _ 15 is the fraction whose numerator is 25 + 15 = 40 and whose denominator is 25 – 15 = 10: = 4.

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